Answer:
Answer: 6.5 moles of silver metal is formed in the given chemical reaction. The moles of excess reagent left are 0.55 moles.
Step-by-step explanation:
To calculate the moles of silver formed and the moles of excess reagent left after the reaction, we need to balance the equation first and need to find the limiting and excess reagent.
The balanced chemical equation is:
Zn + 2AgNO3 ---> Zn (NO3)2 +2Ag
By Stoichiometry:
2 moles of Silver nitrate reacts with 1 mole of Zinc metal
So, 6.5 moles of silver nitrate will react with = 1/2 x 6.5 = 3.25 moles of zinc metal
The required amount of zinc metal is less than the given amount of zinc metal, hence, it is considered as an excess reagent.
Therefore, silver nitrate is the limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of silver nitrate produces 2 moles of silver metal
So, 6.5 moles of silver nitrate will produce = 2/2 x 6.5 = 6.5moles of silver metal.
Number of moles of excess reagent left after the completion of reaction = (3.8 - 3.25)moles = 0.55 moles
Hence, 6.5 moles of silver metal is formed in the given chemical reaction. The moles of excess reagent left are 0.55 moles.