Question

Please help me with this math

Answer 1

`x=\displaystyle(5+√(21))/(2)` or
`x=\displaystyle(5-√(21))/(2)`

Explanation:

Hi there!

`(x+1)^2=7x`

Expand the parentheses:

`x^2+2x+1=7x`

Move 7x to the other side:

`x^2+2x-7x+1=0\\x^2-5x+1=0`

Apply the quadratic formula:

`x=\displaystyle(-b\pm√(b^2-4ac))/(2a)` where
`ax^2+bx+c=0`

Plug in the values a, b and c:

`x=\displaystyle(-(-5)\pm√((-5)^2-4(1)(1)))/(2(1))\\\\x=\displaystyle(5\pm√(25-4))/(2)\\\\x=\displaystyle(5\pm√(21))/(2)`

I hope this helps!