Question

Solve for a.
a^2=-3a+88

Answer 1

`a=8,-11`

Explanation:

`a^2=-3a+88`

`a^2+3a=88`

`a^2+3a-88=0`

`x=(-b\pm√(b^2-4ac) )/(2a)`

`x=(-3\pm√(3^2-4(1)(-88)) )/(2(1))`

`x=(-3\pm√(9+352) )/(2)`

`x=(-3\pm√(361) )/(2)`

`x=(-3\pm19 )/(2)`

`x=-11` and
`x=8`

Therefore, the values of
`a` are 8 and -11.