Question

2 moles of sodium phosphate reacts with 3 moles of

calcium chloride
2Na3PO4 + 3 CaCl2 -> 6 NaCl + Ca2 (PO4)2
using the chemical equation above, how many moles
of NaCl can be produced if one of these is a limiting
reactant?

Answer 1

Answer: 6 moles of NaCl are produced when 2 moles of sodium phosphate reacts with 3 moles of calcium chloride

Step-by-step explanation:

The balanced chemical equation is:

`2Na_3PO_4+3CaCl_2\rightarrow 6NaCl+Ca_3(PO_4)_2`

According to stoichiometry :

2 moles of
`Na_3PO_4` require 3 moles of
`CaCl_2`

Thus both are limiting reagent as both will limit the formation of product.

As 2 moles of
`Na_3PO_4` reacts with 3 moles of
`CaCl_2` give = 6 moles of
`NaCl`

Thus 6 moles of NaCl are produced when 2 moles of sodium phosphate reacts with 3 moles of calcium chloride