Answer:
Option D.
Step-by-step explanation:
First we convert the given reactant masses into moles, using their respective molar masses:
- 4.00 g H₂ ÷ 2 g/mol = 2 mol H₂
- 6.20 g P₄ ÷ 124 g/mol = 0.05 mol P₄
0.05 moles of P₄ would react completely with (6*0.05) 0.3 moles of H₂. There are more H₂ moles than required, meaning H₂ is in excess and P₄ is the limiting reactant.
Now we calculate how many PH₃ moles could be formed, using the number of moles of the limiting reactant:
- 0.05 mol P₄ *
= 0.2 mol PH₃
Finally we convert 0.2 mol PH₃ into grams, using its molar mass:
- 0.2 mol PH₃ * 34 g/mol = 6.8 g
So the correct answer is option D.