Answer:
![\boxed {\boxed {\sf 0.055 \ mol \ CO_2}}](https://img.qammunity.org/2022/formulas/chemistry/college/4sp90lmuddfmudrnrzxbceip0zy9d1cwen.png)
Step-by-step explanation:
To convert form grams to moles, the molar mass must be used. This is the mass (in grams) in 1 mole of a substance.
We can use the values on the Periodic Table. First, find the molar masses of the individual elements: carbon and oxygen.
- C: 12.011 g/mol
- O: 15.999 g/mol
Check for subscripts. The subscript of 2 after O means there are 2 oxygen atoms, so we have to multiply oxygen's molar mass by 2 before adding.
- O₂: 2* (15.999 g/mol)=31.998 g/mol
- CO₂: 12.011 g/mol + 31.998 g/mol =40.009 g/mol
Use the molar mass as a ratio.
![\frac {44.009 \ g\ CO_2}{ 1 \ mol \ CO_2}](https://img.qammunity.org/2022/formulas/chemistry/college/pylhzw88d47jehs2r54ssgovjr068y0zlx.png)
Multiply by the given number of grams.
![2.4 \ g \ CO_2 *\frac {44.009 \ g\ CO_2}{ 1 \ mol \ CO_2}](https://img.qammunity.org/2022/formulas/chemistry/college/dhdooqlgo7qbts9ykuwpymfqr3dkb7ysm7.png)
Flip the fraction so the grams of carbon dioxide cancel.
![2.4 \ g \ CO_2 *\frac { 1 \ mol \ CO_2}{44.009 \ g\ CO_2}](https://img.qammunity.org/2022/formulas/chemistry/college/mrc9ht59j5ratdisvsq4g134g0dkjkdxfs.png)
![2.4 *\frac { 1 \ mol \ CO_2}{44.009}](https://img.qammunity.org/2022/formulas/chemistry/college/hjy0mxtkuo1donh0fk6etufagj6nju9m5x.png)
![\frac { 2.4 \ mol \ CO_2}{44.009}= 0.0545342998 \ mol \ CO_2](https://img.qammunity.org/2022/formulas/chemistry/college/jquryyc6faq6gp4wkh70ljpjov2tc8xbb4.png)
The original measurement of grams has 2 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.
The ten thousandth place has a 5, so we round the 4 to a 5.
![0.055 \ mol \ CO_2](https://img.qammunity.org/2022/formulas/chemistry/college/tjp8vtqwat8ykgatmglhly4fpjymc1z360.png)
2.4 grams of carbon dioxide is about 0.055 moles.