520,853 views
18 votes
18 votes
Mammoth Muffler employs supervisors and helpers. According to the union contract,

a supervisor does 2 brake jobs and 3 mufflers per day, whereas a helper does 6 brake
jobs and 3 mufflers per day. The home office requires enough staff for at least 24 brake
jobs and at least 18 mufflers per day. If a supervisor makes $90 per day and a helper
makes $100 per day, how many of each should be employed to satisfy the constraints
and to minimize the daily labor cost?
What are you trying to maximize or minimize?
What is the function we will use to minimize?
Define the variables used in the problem.
What constraints do we have and what inequalities describe them?
Graph these inequalities on the graph below.
aion
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User Gjulianm
by
2.3k points

1 Answer

11 votes
11 votes

Answer:

3 brakes and Mufflers each one

Explanation:

Employes:

daily production

Supervisor = 2b and 3m

Helper = 6b and 3m

both make 8brakes and 6mufflers daily

3(8b+6m)=24brakes and 18muffles

than means you need 3 Supervisor and 3 Helpers to complete the order

S=3(2b+3m) = 6b + 9m

H=3(6b+3m) = 18m + 9m

3S=$270

3H=$300

Daily cost = $570

I know this is not enough of an answer but I hope this helps a little

User Barum Rho
by
3.5k points
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