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How many moles are in 2.8x10^23 atoms of Calcium?

a. 6.98 moles Ca


b. 0.47 moles Ca


c. 1.1x10^25 moles Ca


d. 1.7x10^47 moles Ca

User Robo Mop
by
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1 Answer

8 votes

Answer:

b. 0.47 moles Ca.

Step-by-step explanation:

Hello there!

In this case, since 1 mole of any element contains 6.022x10²³ atoms of the same, it is possible for us to compute the moles in 2.8x10²³ atoms of calcium via the Avogadro's number:


2.8x10^(23)atomsCa*(1molCa)/(6.022x10^(23)atomsCa)\\\\=0.47molCa

Therefore, the answer would be b. 0.47 moles Ca.

Best regards!

User Riccardo Galli
by
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