Question

1. If you have 1.505 X 10^24 atoms of oxygen in glucose (C1,0), how many grams

of glucose do you have ?

Answer 1

`75.04gC_6H_(12)O_6`

Step-by-step explanation:

Hello!

In this case, since one mol of any atom is related via the Avogadro's number and each mol of glucose has 6 moles of atoms of oxygen, it is possible to obtain the moles of glucose as shown below:

`1.505x10^(24)atomsO*(1molO)/(6.022x10^(23)atoms O)*(1molC_6H_(12)O_6)/(6molO)\\\\=0.4165 mol C_6H_(12)O_6`

Thus, since the molar mass of glucose is 180.15 g/mol, the mass turns out to be:

`0.4165mol*(180.15g)/(1mol) \\\\=75.04gC_6H_(12)O_6`

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