Question

The length of a new rectangular playing field is 7 yards longer than triple the width. If the perimeter of the rectangular playing field is 438 ​yards, what are its​ dimensions?

Answer 1

Explanation:

Width = w

triple the width = 3*w = 3w

Length = 7 yards longer than triple the width = 3w + 7

Perimeter = 438 yards

2*(length +width) = 438

2*(3w+ 7 + w) = 438 {Combine like terms}

2 * (4w + 7) = 438

2*4w +2*7 = 438 {Use distributive property}

8w + 14 = 438 {Subtract 14 from both side}

8w = 438 - 14

8w = 424 {Divide both sides by 8}

w = 424/8

w = 53 yards

Length = 3*53 +7 = 159 + 7 = 166 yards

Width = 53 yards

Length = 166 yards