Answer:
x = log(33)/(3·log(2))
Explanation:
The relevant logarithm relation is ...
log(a^b) = b·log(a)
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Taking the logarithm of both sides of your equation gives ...
2^(3x) = 33
log(2^(3x)) = log(33)
(3x)·log(2) = log(33)
The coefficient of x is 3·log(2). Dividing by that gives the value of x:
x = log(33)/(3·log(2))
x ≈ 1.51851/(3·0.301030) ≈ 1.6814647