Question

Factorise a.x3+4.a.x​

Answer 1

`{ax}^(3) + 4ax \\`

factorise out a and x :

`{ \boxed{answer{= ax( {x}^(2) + 4) }}}\\ but \: farther \: more : \\ = ax( {x}^(2) + {2}^(2) )`

but from general factorization:

`{ \boxed{( {a}^(2) + {b}^(2)) = {(a + b)}^(2) - 2ab }}`

a » x

b » 2

therefore:

`= ax \{ {(x + 2)}^(2) - 2(x)(2) \} \\ \\ = { \boxed{ \boxed{ax( {x + 2)}^(2) - 4x }}}`