Answer:
During the month of September.
Explanation:
The temperature in Beijing, in m months after January, is given by the following equation:
![T(m) = 27\cos{((\pi)/(6)(m-6))} + 45](https://img.qammunity.org/2022/formulas/mathematics/high-school/uobertcaq6zr6541drmvztxpue05894a0x.png)
In which m is the number of months after January.
During which month in the year would the temperature reach 55°F?
We have to find m for which: T(m) = 55. So
![T(m) = 27\cos{((\pi)/(6)(m-6))} + 45](https://img.qammunity.org/2022/formulas/mathematics/high-school/uobertcaq6zr6541drmvztxpue05894a0x.png)
![55 = 27\cos{((\pi)/(6)(m-6))} + 45](https://img.qammunity.org/2022/formulas/mathematics/high-school/e505c12drmb4xn797860j79vcmm2214agb.png)
![27\cos{((\pi)/(6)(m-6))} = 10](https://img.qammunity.org/2022/formulas/mathematics/high-school/ymr4wuo49hu13tyu3fzax57dqcgpdtiexb.png)
![\cos{((\pi)/(6)(m-6))} = (10)/(27)](https://img.qammunity.org/2022/formulas/mathematics/high-school/fw338a1hnlntmcmcddupnkknn31wa5wxvo.png)
Applying the inverse cosine to both sides:
![\cos^(-1){(\cos{((\pi)/(6)(m-6))})} = \cos^(-1){((10)/(27))}](https://img.qammunity.org/2022/formulas/mathematics/high-school/wcpameqv7jjtbrcxathaf3viui0hiqbnb8.png)
![(\pi)/(6)(m-6) = 1.19](https://img.qammunity.org/2022/formulas/mathematics/college/1w04e4ng4i7cpsd4wlclop4g0f98083y50.png)
![\pi(m-6) = 6*1.19](https://img.qammunity.org/2022/formulas/mathematics/high-school/ccsbf1kzjmdykmwwlgm7nq3gghneb86qf3.png)
![\pi m - 6\pi = 6*1.19](https://img.qammunity.org/2022/formulas/mathematics/college/z19fp5vmrs7f9ciayy7m7x79piom6k7beg.png)
![\pi m = 6*1.19 + 6\pi](https://img.qammunity.org/2022/formulas/mathematics/high-school/cxf2jbn5pawr3evs60mmgxahtw2i2tf8ib.png)
![m = (6*1.19 + 6\pi)/(\pi)](https://img.qammunity.org/2022/formulas/mathematics/high-school/o9ng3q8x9y0r1d74d2ijag0ckisnc9p9p3.png)
![m = 8.27](https://img.qammunity.org/2022/formulas/mathematics/college/oybbqk22iy5vwzxnsri6h9ekkj8m62qp8a.png)
8.27 months after January
8.27 + 1 = 9.27, so during the month of September.