Question

Meena's age is four times her daughter's age. Two years ago she was five times herdaughter's age. Find their present ages. pls explain step by step​

Answer 1

8 and 32

Explanation:

let daughter's age be x then Meena's age is 4x

2 years ago daughter's age was x- 2 and Meena's age was 4x - 2

Meena was 5 times her daughter's age then , so

4x - 2 = 5(x - 2)

4x - 2 = 5x - 10 ( subtract 4x from both sides )

- 2 = x - 10 ( add 10 to both sides )

8 = x

Thus

daughter is 8 years and Meena is 4 × 8 = 32 years