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An alternating voltage of 25.0 V is connected across the primary coil of a transformer.

Input Voltage 25 V
ind Output Voltage
50 V Output Current
Input Current 5 A
What is the current across the secondary coil? A 2.5 A C 250 A B D 5.0 A 500 A​

User Dan Midwood
by
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1 Answer

18 votes
18 votes

Answer:

A

Step-by-step explanation:

Wattage = E * I

E = 25

I = 5

Wattage = 25 * 5

Wattage = 125

The secondary, in an ideal transformer has the same wattage.

125 = 50 * I Divide by 50

125/50 = I

I = 2.5

User Tmikeschu
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3.3k points