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17 votes
17 votes
Solve M = 5rt^2- 2rv for v.

Can someone please help with this I’ll put it to 100 points

User Jack G
by
2.4k points

2 Answers

24 votes
24 votes

Answer:


v = -(M-5rt^2)/(2r)

Explanation:


M = 5rt^2 - 2rv

Switch sides


5rt^2-2rv=M

Subtract
5rt^2 from both sides


5rt^2 - 2rv-5rt^2= M -5rt^2

Simplify


-2rv = M - 5rt^2

Divide both sides by
-2r


(-2rv)/(-2r) =(M)/(-2r) -(5rt^2)/(-2r)

Simplify


-(M-5rt^2)/(2r)

User James Gaunt
by
3.1k points
28 votes
28 votes

Answer:

(M-5rt^2)/(-2r) =v

Explanation:

M = 5rt^2- 2rv

Subtract 5rt^2 from each side

M-5rt^2 = 5rt^2- 2rv -5rt^2

M-5rt^2 = - 2rv

Divide each side by -2r

(M-5rt^2)/(-2r) =- 2rv / (-2r)

(M-5rt^2)/(-2r) =v

User Rob Holmes
by
3.0k points