Question

What is the freezing point, in °C,

of a 1.56 m aqueous solution
of K3PO4?
Note: K for water is 1.86 °C/m
Enter rounded answer to three decimal points.

Answer 1

`\boxed{\sf \Delta T_f=K_fm* i}`

• i is vant of factor

For K_3 PO_4

It shall release 3K+ and PO_4- ions

• So vant Hoff factor is 4

Now

`\\ \rm\Rrightarrow \Delta T_f=1.56(4)(1.86)`

`\\ \rm\Rrightarrow \Delta T_f=11.6°C`

It can be freezed easily at room temperature in UK or Siberia

Answer 2

1,380 °C hope this is the right answer