1 Answer

Steven Ventimiglia · Answer 1 · 2022-05-04T20:58:18+0000

Step-by-step explanation:

Given:

$v_0 = 28.0\:\text{ft/s}$

$v = 50.0\:\text{ft/s}$

$t = 7.40\:\text{s}$

First, we calculate the acceleration of the car during this time:

$v = v_0 + at \Rightarrow a = (v - v_0)/(t)$

Plugging in the given values, we get

$a = \frac{50.0\:\text{ft/s} - 28.0\:\text{ft/s}}{7.40\:\text{s}} = 2.97\:\text{ft/s}^2$

Now that we have the value for the acceleration, we can solve for the distance traveled during the time t:

x = v_0t + (1)/(2)at^2

$\:\:\:\:=(28.0\:\text{ft/s})(7.40\:\text{s})$

$\:\:\:\:\:\:\:\:\:\:\:\:+ (1)/(2)(2.97\:\text{ft/s}^2)(7.40\:\text{s})^2$

$\:\:\:\:= 289\:\text{ft}$

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