Question

6.3 gram of HNO3 as mass of nitrate

Answer 1

Moles of HNO 3

​ = 6.3/63 = 0.1 moles

HNO3 has 1 atom of H , 1 atom of N , 3 atoms of O

No of atoms = moles of molecule × atomicity of atom × avogadro number

No of atoms of H =0.1×1×6.023×10^23

= 6.023×10^22

No of atoms of N =0.1×1×6.023×10^23

= 6.023×10 ^22

No of atoms of O =0.1×3×6.023×10 ^23

= 18.069×10 ^22