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What is the values of pOH 0.020M HNO3

User Gchtr
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2 Answers

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10 votes

Final answer:

The value of pOH for a 0.020 M HNO3 solution is 1.70, and the pH value is 12.30.

Step-by-step explanation:

The value of pOH for a 0.020 M HNO3 solution can be calculated using the formula pOH = -log([OH¯]). Since HNO3 is a strong acid, it completely dissociates in water to form H3O+ ions. Therefore, the concentration of OH- ions is equal to 0.020 M. Plugging this value into the formula, we get pOH = -log(0.020) = 1.70.

The pH value can be calculated using the formula pH = 14 - pOH. Therefore, pH = 14 - 1.70 = 12.30.

User Jay Dangar
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10 votes
10 votes

Answer:

pOH is 12.3

Step-by-step explanation:

let's first get the pH of nitric acid:


{ \sf{pH = - log[H {}^( + ) ]}}

but:

[H†] = 0.020 M

therefore:


{ \sf{pH = - log(0.020) }} \\ { \sf{pH = 1.7}}

but, pOH = 14 - pH


{ \sf{pOH = 14 - 1.7}} \\ { \sf{pOH = 12.3}}