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43 votes
43 votes
Class 10 cbse

Q) Four years ago George was four times older than his daughter. After four years, George will be 2 years more than two times the age of his daughter. Find the present age of George and his daughter.

Please answer asap

User GingerPlusPlus
by
2.2k points

2 Answers

27 votes
27 votes

Answer:

George Washington 67 and sister 63

User Duncan Lukkenaer
by
2.7k points
24 votes
24 votes

Answer: 28

Explanation:

Let the present age of George be = x years

and present age of her daughter is = y years

4 years ago,

George age be = x - 4

Daughter age be = y - 4

After four years,

George age be = x +4

Daughter age be = y+ 4

Substitute the value of x in equation 2

Value of y put in equation 1

➡x= 28

So, the present age of George is 28 years and his daughter's age is 4 years.

User LostBoy
by
2.8k points
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