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Find the linear function f if f^-1(2)=-1 and f^-1 (-9)=3

User Fender
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1 Answer

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17 votes

Answer:


\displaystyle f(x) = -(11)/(4)(x + 1) + 2

Explanation:

We want to find the linear function given that:


f^(-1)(2) = -1\text{ and } f^(-1) (-9) = 3

Recall that by the definition of inverse functions:


\displaystyle \text{If } f(a) = b\text{ then } f^(-1)(b) = a

In other words, f(-1) = 2 and f(3) = -9.

This yields two points: (-1, 2) and (3, -9).

Find the slope of the linear function:


\displaystyle m = (\Delta y)/(\Delta x) = ((-9) - (2))/((3) -(-1)) = -(11)/(4)

From point-slope form:


\displaystyle y - (2) = -(11)/(4)( x- (-1))

Hence:


\displaystyle f(x) = -(11)/(4)(x + 1) + 2

We can simplify if desired:


\displaystyle f(x) = -(11)/(4)x -(3)/(4)

User Carmenism
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