Answer:
or
![3√(13)](https://img.qammunity.org/2022/formulas/mathematics/high-school/a0etc6aoph5vnnvpxe7cvrjutswgwyebqg.png)
Explanation:
The formula for finding the any side of the triangle is
![a^(2)+b^(2) =c^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/zxlkpvs3xaj1g4rjmikioedqfav91ywhec.png)
We know that a=2 and c=11, so we can go ahead and plug those into the formula.
![2^(2)+b^(2) =11^(2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/j7ps4075n33yzb8seszhxmkjdtudgmwlxu.png)
![4+b^(2) =121](https://img.qammunity.org/2022/formulas/mathematics/high-school/t1m7v538rfmlgmmphiyt1gt52avo9dx5t8.png)
To find side b, we have to make it alone on one side. Subtract 4 on both side.
![b^(2) =117](https://img.qammunity.org/2022/formulas/mathematics/high-school/v7w9ixhm4uajrhj998pac2xkg3gsdiaoaf.png)
Now square root both sides, and that leaves us with:
or
![3√(13)](https://img.qammunity.org/2022/formulas/mathematics/high-school/a0etc6aoph5vnnvpxe7cvrjutswgwyebqg.png)