Question

We need help finding the means of the sides of this figure.

(Photo attached)

Thank you

Answer 1

3) 5

4) 8.2

5) 6.8

6)FG = 6.4

7) EF = 3.6

8)DF = 4.8

Explanation:

From the attached triangle, using trigonometric ratio we can find ∠G as; tan^(-1) (6/8)

Thus, ∠G = 36.87°

Still using trigonometric ratios;

FG/8 = cos 36.87°

FG = 8 cos 36.87°

FG = 6.4

3) EF + FG = EG

Since EG is 10, mean of EF and FG = 10/2 = 5

4) mean of EG and FG = (10 + 6.4)/2 = 8.2

5) EF + FG = EG

Thus; EF = EG - FG

EF = 10 - 6.4

EF = 3.6

Mean of EG and EF = (10 + 3.6)/2 = 6.8

6) FG = 6.4

7) EF = 3.6

8) Using trigonometric ratio;

DF/8 = sin 36.87

DF = 8 × 0.6

DF = 4.8