Question

6. A rectangle has a perimeter of 62 feet. If its length is 9 feet longer than its width, find

the dimensions of the rectangle.
62ft

Answer 1

length = 20 ft, width = 11 ft

Explanation:

let w be width, then length = w + 9

The opposite sides of a rectangle are equal , then

2w + 2(w + 9) = 62

2w + 2w + 18 = 62

4w + 18 = 62 ( subtract 18 from both sides )

4w = 44 ( divide both sides by 4 )

w = 11

and w + 9 = 11 + 9 = 20

then width = 11 ft and length = 20 ft