Question

Rt = R1 + R2 + R3


`(1)/(rt) = (1)/(r1) + (1)/(r2) + (1)/(r3)`

If R1 = 4Ω , R2 = 6Ω and R3 = 8Ω (Ω= ohm)


Calculate: 4.1.1 Rt (series)
4.1.2 Rt (parallel)





​

Answer 1

In series:

`(1)/(r) = (1)/(r_(1) ) + (1)/(r _(2) ) + (1)/(r_(3) )`

`(1)/(r) = (1)/(4) + (1)/(6) + (1)/(8) \\ \\ (1)/(r) = (13)/(24) \\ \\ r = (24)/(13) \\ { \underline{r = 1.85 \: Ω}}`

In parallel:

`r = r _(1) + r _(2) + r _(3) \\ r = 4 + 6 + 8 \\ r = 18Ω`