Question

What is the equation of a line perpendicular to y = 6x - 5 that passes through the point (6,-3)?

Answer 1

Explanation:

The product of slope of 2 straight lines perpandicular each other is -1.

Now, The slope of the original equation is 6. We wish to find the slope m of the perpendicular line. So

`6m = - 1`

`m = - (1)/(6)`

Now substituting the slope m and the point (6, -3) into the perpandicular line to solve for the y intercept.

`y = mx + c`

`- 3 = 6( - (1)/(6) ) + c`

`c = - 2`

Therefore, the equation of the perpandicular line is

`y = - (1)/(6) x - 2`