Question

aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 344 mL

Answer 1

Probably 928.8 bc most of the times mass is bigger than volume and density. ( I got it by multiplying density and volume.)

Answer 2

`\boxed {\boxed {\sf 928.8 \ grams}}`

Step-by-step explanation:

Density is the mass per unit volume of a substance. The following formula is used for calculating density.

`\rho= (m)/(v)`

We know the density of aluminum is 2.70 grams per milliliter. The mass is unknown, but we know the piece of aluminum has a volume of 344 milliliters.

• ρ= 2.70 g/mL
• v= 344 mL

Substitute these values into the formula.

`2.70 \ g/mL = \frac {m}{344 \ mL}`

We are solving for the mass, so we must isolate the variable m. It is being divided by 344 milliliters. The inverse operation of division is multiplication. Multiply both sides of the equation by 344 mL.

`344 \ mL *2.70 \ g/mL = \frac {m}{344 \ mL} * 344 \ mL`

`344 \ mL *2.70 \ g/mL =m`

The units of milliliters cancel.

`344 *2.70 \ g=m`

`928.8 \ g =m`

The mass of the piece of aluminum is 928.8 grams.