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3(4x^2y^3 + 2x^3) – 4(9x^3y^2 – 6x^2y^3)
How to solve pls?

User Richy
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1 Answer

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22 votes

Answer:


3(4 {x}^(2) {y}^(3) + 2 {x}^(3)) - 4(9 {x}^(3) {y}^(2) - 6 {x}^(2) {y}^(3) ) \\ = (12 {x}^(2) {y}^(3) + 6 {x}^(3) ) - (36{x}^(3) {y}^(2) - 24{x}^(2) {y}^(3)) \\ = (12 {x}^(2) {y}^(3) + 6 {x}^(3) ) + ( - 36{x}^(3) {y}^(2) + 24{x}^(2) {y}^(3)) \\ = - 36{x}^(3) {y}^(2) + 36x^(2) {y}^(3) + 6 {x}^(3)

I hope I helped you^_^

User Mzu
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