67.2k views
12 votes
A fruit stand has to decide what to charge for their produce. They need $10 for 4 apples and 4 oranges.

They also need $12 for 6 apples and 6 oranges. We put this information into a system of linear equations,

Can we find a unique price for an apple and an orange?

A. Yes; they should charge $1.00 for an apple and $1.50 for an orange

B. Yes; they should charge for $1.00 for an apple and $1.00 for an orange

C. No; the system has many solutions

D. No; the system has no solution

(This is from Khan academy)

User Ygogia
by
6.2k points

1 Answer

9 votes

Given 4 apples and 4 oranges cost = $10.

6 apples and 6 oranges = $12.

Let us assume cost of each apple = $x.

Cost of each orange = $y.

4 apples and 4 oranges cost can be given by equation:

4x+4y = 10.

Dividing both sides by 4, we get

x+y = 2.50 ---------------equation (1)

6 apples and 6 oranges cost can be given by equation:

6x+6y = 12.

Dividing both sides by 6, we get

x+y =2 ---------------equation (2).

We can see from equation (1) and equation (2), that x+y equals 2 and 2.5.

But that doesn't seem to be true.

So, we could just say that we can't find a unique price for an apple and an orange for the given information.

User HamzaGhazouani
by
7.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.