Question

Find the midpoint is the assignment.

Answer 1

(3, - 6 )

Explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

(
`(x_(1)+x_(2) )/(2)` ,
`(y_(1)+y_(2) )/(2)` )

Here (x₁, y₁ ) = (10, - 3) and (x₂, y₂ ) = (- 4, - 9) , then

midpoint = (
`(10-4)/(2)` ,
`(-3-9)/(2)` ) = (
`(6)/(2)` ,
`(-12)/(2)` ) = (3, - 6 )

Answer 2

• (10,-3)
• (-4,-9)

`\\ \rm\hookrightarrow (x,y)=\left((x_1+x_2)/(2)_(y_1+y_2)/(2)\right)`

`\\ \rm\hookrightarrow (x,y)=\left((10-4)/(2),(-3-9)/(2)\right)`

`\\ \rm\hookrightarrow (x,y)=\left((6)/(2),(-12)/(2)\right)`

`\\ \rm\hookrightarrow (x,y)=(3,-6)`