291,865 views
12 votes
12 votes
F(x)=2x^2-5;find when f(x)=-7​

User Ruam Pimentel
by
2.7k points

2 Answers

27 votes
27 votes

Answer:

x=i or no solution exists depending on the user's grade

Explanation:

f(x) = 2x^2-5

-7 = 2x^2-5

-2 = 2x^2, x^2=-1, x=i

User Conmak
by
3.2k points
18 votes
18 votes

Answer:

±i = x

Explanation:

f(x)=2x^2-5;

f(x)=-7​

-7 = 2x^2 -5

Add 5 to each side

-7+5 = 2x^2 -5+5

-2 =2x^2

Divide by 2

-2/2 =2x^2 /2

-1 = x^2

Take the square root of each side

sqrt(-1) = sqrt(x^2)

±i = x

User Leonela
by
2.6k points