Question

Two 31-m long parallel wires are 0.155 m apart. Each carries 168 A of current. What is the magnitude of the force between the wires? Please give your answer in Newtons.

Answer 1

The magnitude of magnetic force between the two parallel wires is 1.13 N.

Step-by-step explanation:

Given;

length of each wire, l = 31 m

distance between the two parallel wires, r = 0.155 m

current on each wire, I = 168 A

The magnitude of magnetic force between the two parallel wires is calculated as;

`F = (\mu _oI_1I_2 L)/(2\pi r) \\\\F = ((4\pi * 10^(-7)) * (168)^2 * (31))/(2\pi * 0.155) \\\\F = 1.13 \ N`

Therefore, the magnitude of magnetic force between the two parallel wires is 1.13 N.