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38 votes
Given the function y = x2 + 2x - 8, what are the values of x when y = 3?

User Sevki
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1 Answer

11 votes
11 votes

Answer:


x = - 1 + 2 √(3)


x = - 1 - 2 √(3)

Explanation:


{x}^(2) + 2x - 8= 3


{x}^(2) + 2x = 11

Complete the square


((2)/(2) ) {}^(2) = 1

so


{x}^(2) + 2x + 1 = 11 + 1


{x}^(2) + 2x + 1 = 12


( x + 1) {}^(2) = 12


x + 1 = √(12)


x = - 1 + √(12)

or


x + 1 = - √(12)


x = - 1 - √(12)

If you want it simplified, you could say

User Danigb
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