Question

5. An electron is separated from a proton by a distance of 1.00 10^-10 m. What is the magnitude of the electric force between them?​

Answer 1

2.304 * 10^-10N

Step-by-step explanation:

The magnitude of the force is expressed as;

F = kq1q2/r²

k is the coulomb constant

q1 id the charge on the electron = -1.6*10^-19C

q2 is the charge on the proton = 1.6*10^-19C

k = 9*10^9

Substitute

F = (9*10^9)*( -1.6*10^-19)( 1.6*10^-19)/(1.00 10^-10)^2

F = 9*10^9*-2.56*10^-38/1.00 10^-20

F = -23.04*10^-29/1.00 10^-20

F = -23.04 * 10^(-29+20)

F = -23.04 * 10 ^-9

F = -2.304 * 10 ^ -10N

Hence the magnitude of the electric force between them is

2.304 * 10^-10N