Question

The length of a rectangle is 5 yd longer than its width.

If the perimeter of the rectangle is 62 yd, find its length and width.

Answer 1

w = 13yd, l = 18yd

Explanation:

let x be width, so x+5 = length

Perimeter is sum of all 4 sides, and since opposite sides equal in rectangle,

P = 2(l+w)

= 2(x+5 +x)

= 4x + 10

Since perimeter is give as 62yd, equation is

4x + 10 = 62

4x = 52

x = 13