Answer:
First thing is that word “autonomous” given in the question is actually “ autosomal”.
Now let's start solution:
Frequency of dominant allele “A” is denoted by p.
Here p = 0.6
Frequency of recessive allele “a” is denoted by q.
According to Hardy - Weinberg equilibrium
p + q = 1
Hence q = 1 - p = 1 - 0.6 = 0.4
Now in question what is asked is about frequency of recessive phenotype (aa).
According to Hardy - Wienberg equilibrium frequency of recessive phenotype is q2 (q square).
Frequency of recessive phenotype is = q2 = 0.4 x 0.4 = 0.16
Now Number of recessive phenotype in a population of 10000 is
= frequency of recessive phenotype x total population
= q2 x 10000
= 0.16 x 10000
= 1600
I answer you other question.
I apologize. it's mistakenly