Question

Una carga de -10Mc está situada a 20cm delante de otra carga de 5 Mc. Calcular la fuerza electrostática en Newton ejercida por una carga sobre la otra. a).- Representar la Fuerza Electrostática. b).- Calcular la Intensidad de las Fuerzas.

Answer 1

a) force between them is attraction, b) F = 1.125 10⁻² N

Step-by-step explanation:

In this case the electric force is given by Coulomb's law

F =
`k (q_1q_2)/(r^2)`

In the exercise they give us the values ​​of the loads

q1 = - 10 mC = -10 10⁻³ C

q2 = 5 mC = 5 10⁻³ C

d = 20 cm = 0.20 m

let's calculate

F = 9 10⁹
`(10 \ 10^(-3) \ 5 \ 10^(-3))/(0.20^2)`

F = 1.125 10⁻² N

To find the direction of the force we use that charges of the same sign repel each other, as in this case there is a positive and a negative charge, the force between them is attraction