Question

Peter took three photos. The photos show a total of 44 birds. The second photo has 9

fewer birds than the first photo. The third photo has 5 more birds than the first photo.
How many birds are in the first photo?

Answer 1

16

Explanation:

given,

The photos show a total of 44 birds.

The second photo has 9 fewer birds than the first photo.

The third photo has 5 more birds than the first photo.

so first photo be X(let)

second=x-9

third=X+5

we know,

X+(X-9)+(X+5)=44

or,3x-4=44

or,×=44+4/3

or,X=48/3=16

Answer 2

16

Explanation:

let x = the number of birds in the first photo

let y = the total number of birds

1st photo = x

2nd photo = 9 fewer birds than 1st photo = x - 9

3rd photo = 5 more birds that 1st photo = x + 5

Therefore,

x + (x - 9) + (x + 5) = y

We know that the total number of birds is 44, so y = 44

⇒ x + (x - 9) + (x + 5) = 44

⇒ x + x - 9 + x + 5 = 44

⇒ 3x - 4 = 44

⇒ 3x = 44 + 4 = 48

⇒ x = 48 ÷ 3 = 16

So if x = 16 and x = the number of birds in the 1st photo,

there are 16 birds in the 1st photo.