If y - 1/y =8 then find the value of y^2-1/y^3

Marc Bernier asked May 10, 2022

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Marc Bernier asked May 10, 2022

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30 votes

Explanation:

${y}^(2) - \frac{1}{ {y}^(3) }$

factorise out y² ;

$= {y}^(2) (1 - (1)/(y) ) \\ \\ = 8 {y}^(2)$

Krossovochkin answered May 16, 2022

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