Question

F(x) = Square root of quantity x plus seven. ; g(x) = 8x - 11 Find f(g(x)). (1 point)

f(g(x)) = 2 Square root of quantity two x plus one
f(g(x)) = 8 Square root of quantity x plus seven - 11
f(g(x)) = 8 Square root of quantity x plus four
f(g(x)) = 2 Square root of quantity two x minus one

Answer 1

`\\ \sf\longmapsto f(x)=√(x+7)`

`\\ \sf\longmapsto g(x)=8x-11`

• g(x) will be put on the place of x

`\\ \sf\longmapsto f(g(x))=√(8x-11+7)`

`\\ \sf\longmapsto f(g(x))=√(8x-4)`

`\\ \sf\longmapsto f(g(x))=√(4(2x-1))`

`\\ \sf\longmapsto f(g(x))=2√(2x-1)`

Answer 2

2 sqrt(2x-1)

Explanation:

f(x) = sqrt(x+7)

g(x) = 8x-11

f(g(x))=

Place g(x) in for x in the function f(x)

f(g(x)) = sqrt( 8x-11 +7)

= sqrt( 8x -4)

Factor out 4

= sqrt( 4(2x-1)

= 2 sqrt(2x-1)