Question

PLS HELP!!
what is the value of x?
log2(x+7) = 2​

Answer 1

Answer: Choice A) -3

Work Shown:

`\log_(2)(x+7) = 2\\\\x+7 = 2^2\\\\x+7 = 4\\\\x = 4-7\\\\x = -3\\\\`

Which leads us to choice A. In the second step, I used the rule that
`\log_b(y) = x` is equivalent to
`y = b^x`. For each equation, the b is the base. Note how logs undo exponents and vice versa.

Answer 2

-3

Explanation:

log2(x+7) = 2​

Raise each side by base 2

2^log2(x+7) = 2^2​

x+7 = 4

Subtract 7 from each side

x+7-7 = 4-7

x=-3