Question

2. A parallel-plate capacitor has a capacitance of C. If the area of the plates is doubled and

the distance between the plates is doubled, what is the new capacitance?
A) C/4
B) C/2
C)C
D) 4C

Answer 1

(C)

Step-by-step explanation:

The capacitance C of a parallel plate capacitor is given by

`C = \epsilon_0 (A)/(d)`

Let C' be the new capacitance where the area and the plate separation distance are doubled. This gives us

`C' = \epsilon_0(A')/(d') = \epsilon_0\left((2A)/(2d)\right) = \epsilon_0 (A)/(d) = C`