Question

What is the equation in point-slope form of the line that passes through the points (2,-3) and (-5,8)?

Answer 1

y+3=-11/7(x-2)

Explanation:

m=(y2-y1)/(x2-x1)

m=(8-(-3))/(-5-2)

m=(8+3)/-7

m=11/-7

y-y1=m(x-x1)

y-(-3)=-11/7(x-2)

y+3=-11/7(x-2)