Question

Mixture Problem A solution contains 15 milliliters of HCI

and 42 milliliters of water. If another solution is to have
the same concentration of HCl in water but is to contain
140 milliliters of water, how much HCI must it contain?

Answer 1

Explanation:

This is a straight proportion problem.

15/42 = x/140 Cross Multiply

15*140 = 42 * x

2100 = 42x Divide by 42

2100/42 = x

x = 50 ml of HCl will be needed.