Question

What is the equation of the line that passes through the point (-4, -7) and has a

slope of 2/3 ?

Answer 1

Explanation:

(-4 , -7) ; slope = (2/3)

y -y1 =m(x-x1)

`y -[-7]=(2)/(3)(x-[4])\\\\y+7 = (2)/(3)(x+4)\\\\y+7=(2)/(3)x+4*(2)/(3)\\\\y +7 = (2)/(3)x+(8)/(3)\\\\y=(2)/(3)x+(8)/(3)-7\\\\y=(2)/(3)x+(8)/(3)-(7*3)/(1*3)\\\\y=(2)/(3)x+(8)/(3)-(21)/(3)\\\\y=(2)/(3)x-(13)/(3)`