Question

Roll a dice six times. Find the probability that :

a . The back of the dot appears exactly 4 times ;

Answer 1

0.804% to 3 dec places.

Explanation:

If the first 4 throws are a dot and the next 2 are not:

Probability = (1/6)^4 * (5/6)^2

= 25/46656

There are 6C4 ways for this to happen

6C4 = (6*5*4*3)/ (4*3*2*1) = 15 ways.

So The required probability = (25*15)/46656

= 125/15552

= 0.00804

= 0.804%

Answer 2

2/3???

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