Answer:
D
Explanation:
Given a tangent and a secant from an external point to the circle, then
The product of the external part and the whole secant is equal to the square of the tangent, that is
8(8 - 6 + 2x) = 12²
8(2 + 2x) = 144 ( divide both sides by 8 )
2 + 2x = 18 ( subtract 2 from both sides )
2x = 16 ( divide both sides by 2 )
x = 8
Then
GH = - 6 + 2x = - 6 + 2(8) = - 6 + 16 = 10 → D