Question

Question 8b , thanks

Answer 1

Explanation:

`a = (2b+1)/(3b-1)`

b = 2/3

`2b + 1 = 2*(2)/(3)+1\\\\=(4)/(3)+1\\\\=(4)/(3)+(3)/(3)\\\\=(7)/(3)\\\\3b-1 = 3*(2)/(3)-1\\\\=2- 1 = 1\\\\\\`

`a = (2b+1)/(3b-1)\\\\a=((7)/(3))/(1)\\\\=(7)/(3)\\\\`

a = 7/3

b)

`(2b+1)/(3b-1)=a\\\\`

Cross multiply,

2b + 1 = a*(3b - 1)

2b + 1 = a*3b - 3*a

2b + 1 = 3ab- 3a

2b = 3ab - 3a - 1

2b - 3ab = -3a - 1

b(2 - 3a) = -3a - 1

`b =(-3a - 1)/(2 - 3a)`