Question

(2+1/2) (2^2-1+1/4) find the expression in the form of cubes and differences of two terms.​

Answer 1

Use the algebraic identity given below

`\boxed{\sf a^3-b^3=(a+b)(a^2-ab+b^2)}`

`\\ \sf\longmapsto (2+(1)/(2))(2^2-1+(1)/(4))`

`\\ \sf\longmapsto (2+(1)/(2))(2^2-2* (1)/(2)+(1)/(2)^2)`

• Here a =2 and b=1/2

`\\ \sf\longmapsto 2^3-(1)/(2)^3`

`\\ \sf\longmapsto 8-(1)/(8)`

Answer 2

Consider the following identity:

• a³ - b³ = (a + b)(a² - ab + b²)

Let a = 2, b = 1/2

• (2 + 1/2)(2² - 2*1/2 + 1/2²) =
• 2³ - (1/2)³ =
• 8 - 1/8